Question

Chris Paul is a 6 foot tall basketball player for the Phoenix Suns. He is known for his ball dribbling skills and ability to make most of his free throw shots. The free throw line is exactly 15 feet from the basket. The basket is 10 feet off the ground. What angle of elevation does Chris Paul have from his eye sight up to the hoop? Write an equation and show yor work. ROUND TO THE NEAREST DEGREE.​

Answer 1

Chris Paul's angle of elevation from his eyesight to the hoop is approximately 33.7 degrees.

Step-by-step explanation:

To find the angle of elevation from Chris Paul's eyesight to the hoop, we can use trigonometry. Let's call the angle of elevation θ. Using the given information, we have:

The height of the hoop (h) = 10 ft

The distance from the free throw line to the hoop (d) = 15 ft

We can use the tangent function to find the angle:

tan(θ) = h/d

tan(θ) = 10/15

θ = tan-1(10/15)

Using a calculator, we can find that θ ≈ 33.7 degrees.