Final answer:
The area of the larger square, with side length 8 inches, is four times greater than the area of the smaller square, with side length 4 inches.
Step-by-step explanation:
The student is asking about the area of a larger square compared to a smaller square. To determine this, we can use the concept of scale factor in geometry. Given that the side length of the first, smaller square is 4 inches, the side of the larger square will be twice this length, which is 4 inches times 2, resulting in 8 inches. To compare the areas of two squares, we square their side lengths. The area of the smaller square is 4 inches times 4 inches, which is 16 square inches. The area of the larger square is 8 inches times 8 inches, which is 64 square inches. Therefore, the area of the larger square is four times greater than that of the smaller square.