Answer:
1.46878825 g O_3
Step-by-step explanation:
the balanced equation is:
2 KClO_3 = 2 KCl + 3 O_2
using stoichiometry, you can find the amount of O_2 produced from 2.5 g KClO_3
2.5 g KClO_3 x (1 mol / 122.55 g KClO_3) x (3 mol O_3 / 2 mol KClO_3) x (48 g O_3 / 1 mol O_3) = 1.46878825 g O_3