Question

If 3.01 mols of KBr were dissolved in 1030 mL of water, KBr would be the solute Water would be the solvent And the concentration would be [Select]

Answer 1

The concentration of a KBr solution with 3.01 moles of KBr dissolved in 1030 mL of water would be approximately 2.922 M.

Step-by-step explanation:

If 3.01 moles of KBr were dissolved in 1030 mL (which is 1.030 liters) of water, the concentration would be calculated as the number of moles of solute (KBr) divided by the volume of the solution in liters. Since molarity (M) is defined as moles per liter, we would have:

Molarity (M) = Moles of solute / Volume of solution in liters

Molarity (M) = 3.01 moles KBr / 1.030 liters of solution

The concentration of the KBr solution would therefore be approximately 2.922 M (molar), assuming that the addition of KBr does not significantly change the volume of the solution.