Final answer:
To find the number of grams of Fe2O3 formed when 6.7 g of Fe reacts completely with oxygen, we need to use the stoichiometry of the balanced chemical equation.
Step-by-step explanation:
To find the number of grams of Fe2O3 formed when 6.7 g of Fe reacts completely with oxygen, we need to use the stoichiometry of the balanced chemical equation. The balanced equation for the reaction is:
4Fe + 3O2 → 2Fe2O3
The molar mass of Fe2O3 is 159.70 g/mol. Using the molar ratio between Fe and Fe2O3 (4 mol Fe : 2 mol Fe2O3), we can calculate the number of moles of Fe2O3 formed:
(6.7 g Fe) ÷ (55.85 g/mol Fe) × (2 mol Fe2O3) ÷ (4 mol Fe) = 2.84 g Fe2O3