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A penny at rest is dropped from the top of a tall stairwell. What is the pennys velocity after it has fallen for 2 seconds?

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Final answer:

The penny's velocity after falling for 2 seconds will be 19.6 m/s downward, calculated using the formula V = Vi + gt with an initial velocity of 0 m/s and gravitational acceleration of 9.8 m/s².

Step-by-step explanation:

The penny's velocity after it has fallen for 2 seconds can be calculated using the equation of motion under the influence of gravity, assuming that the initial velocity (Vi) is zero since it was dropped from rest. The formula to find the final velocity is V = Vi + gt, where g is the acceleration due to gravity (9.8 m/s²) and t is the time in seconds. Hence, after 2 seconds, the penny's velocity would be 0 m/s + (9.8 m/s² * 2 s) = 19.6 m/s downward.

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