Final answer:
Without a relevant chemical equation, it is not possible to calculate the grams of CaCO3 produced from 4.7 moles of H2O. CaCO3 and H2O are not directly related as reactants and products in a stoichiometric chemical reaction.
Step-by-step explanation:
To determine how many grams of CaCO3 are produced from 4.7 moles of H2O, we would need a balanced chemical equation that describes a reaction involving H2O and producing CaCO3. Unfortunately, with the information given, it is not possible to directly calculate the grams of CaCO3 produced from H2O without additional context or a relevant chemical equation because H2O and CaCO3 are not reactants and products in a single stoichiometric chemical reaction.
However, as an example and for educational purposes, we can reference a typical stoichiometric calculation using the provided example 6.4.1: If the balanced chemical equation were CaCO3 + 2 HCl → CaCl2 + CO2 + H2O, and you started with 2.09 moles of HCl, you would produce 2.09 moles of H2O. However, the CaCO3 would be a reactant and not produced in this reaction.