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A scientist uses a submarine to study ocean life.

A) She begins 93 feet below sea level.
B) After traveling directly up for 10 seconds, she's 81 feet below sea level.
Find the rate of change in the submarine's elevation in feet per second. Round your answer to the nearest tenth.

User Parvus
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Final answer:

The submarine's rate of change in elevation is 1.2 feet per second when rounded to the nearest tenth.

Step-by-step explanation:

The rate of change in the submarine's elevation is calculated by considering the change in depth and the time taken for this change. The submarine starts at 93 feet below sea level and ascends to 81 feet below sea level, so the change in depth is 93 feet - 81 feet = 12 feet. This ascent took 10 seconds. Therefore, the rate of change is 12 feet / 10 seconds = 1.2 feet per second. When rounded to the nearest tenth, the rate of change is 1.2 feet per second.

User Sey
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