200k views
5 votes
A car traveling initially at 6.96 m/s accelerates at the rate of 0.658 m/s² for 5.06 s. What is its velocity at the end of the acceleration?

A. 10.45 m/s
B. 3.33 m/s
C. 15.09 m/s
D. 0.47 m/s

1 Answer

0 votes

Final answer:

Using the kinematic equation v = u + at, the final velocity of the car after accelerating for 5.06 s is found to be approximately 10.29 m/s, which is closest to the listed option A: 10.45 m/s.

Step-by-step explanation:

The question involves calculating the final velocity of a car after accelerating for a certain period of time, given its initial velocity and acceleration rate. This is a classic problem in kinematics, a branch of physics that deals with the motion of objects.

To find the final velocity (v), we use the kinematic equation: v = u + at, where u is the initial velocity, a is the acceleration, and t is the time. Here, u = 6.96 m/s, a = 0.658 m/s², and t = 5.06 s.

Substituting the given values into the equation:

  • v = 6.96 m/s + (0.658 m/s² × 5.06 s)
  • v = 6.96 m/s + 3.32908 m/s
  • v = 10.28908 m/s

Therefore, the car's velocity at the end of the acceleration is approximately 10.29 m/s, which when rounded, is closest to option A, 10.45 m/s.

User Prashanth B
by
7.7k points