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Find the perimeter of a triangle with the side lengths of 3X, (X-1), and 2(X+4).

A) 6X+4
B) 6X+14
C) 8X+6
D) 10X−2

User Jule
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1 Answer

6 votes

Final answer:

The perimeter of the triangle with given side lengths 3X, (X-1), and 2(X+4) is 6X + 7.

Step-by-step explanation:

To find the perimeter of a triangle with side lengths of 3X, (X-1), and 2(X+4), we need to add up the lengths of all three sides. The perimeter is the sum of all the side lengths.

Perimeter = 3X + (X-1) + 2(X+4)

Simplifying the expression, we get Perimeter = 3X + X - 1 + 2X + 8 = 6X + 7.

Therefore, the correct answer is 6X + 7 (option B).

User Arnaud Leyder
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7.6k points