100k views
2 votes
Suppose x has a distribution with a mean of 70 and a standard deviation of 9. Random samples of size n=36 are drawn

Suppose x has a distribution with a mean of 70 and a standard deviation of 9. Random-example-1
User Sam Gomena
by
8.0k points

1 Answer

6 votes

The x distribution is a normal distribution with a mean of 70 and a standard deviation of 9. The z value corresponding to x = 67 is -0.33. The probability of x being less than 67 is approximately 0.3707.

Step-by-step explanation:

The x distribution is a normal distribution with a mean of 70 and a standard deviation of 9.

To find the z value corresponding to x = 67, we subtract the mean from x and divide by the standard deviation. So, (67-70)/9 = -0.33. Therefore, z = -0.33.

To find P(x < 67), we need to find the z score corresponding to x = 67 and then find the area under the curve to the left of that z score. Using a z-table or calculator, we find that P(z < -0.33) ≈ 0.3707.

Since the distribution of sample means follows a normal distribution with the same mean as the population mean but a smaller standard deviation (standard deviation of the population divided by the square root of the sample size), it is unlikely for a random sample of size 36 to have a sample mean less than 67. Therefore, it would be unusual for a random sample of size 36 to have a sample mean less than 67.

User Sujen
by
8.7k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.