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The sum of four consecutive odd integers is 5 less than 3 times the second number. What are the numbers?​

User Osantana
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Answer:

Four consecutive odd integers are: 2n+1, 2n+3, 2n+5 and 2n+7

Three times the sum of the first and fourth then are 3(2n+1 + 2n+7)

80 less than 4 times the sum of the second and third then are 4(2n+3 + 2n+5) - 80

Since the two are equal:

3(2n+1 + 2n+7) = 4(2n+3 + 2n+5)-80

expanding the brackets:

6n+3 + 6n + 21 = 8n + 12 + 8n + 20 - 80

combining like terms

3 + 21 - 12 -20 + 80 = 8n + 8n - 6n - 6n

72 = 4n

Explanation:

User BunkerMentality
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