Final answer:
None of the given ordered pairs lie on the graph of the exponential function f(x) = -3(x-1) + 2.
Step-by-step explanation:
The given exponential function is f(x) = -3(x-1) + 2.
To find the ordered pairs that lie on the graph of the exponential function, we need to substitute the given x-values into the function and solve for the corresponding y-values.
- For option (a) (4, -25):
- f(4) = -3(4-1) + 2 = -3(3) + 2 = -9 + 2 = -7 which is not equal to -25. So, (4, -25) does not lie on the graph.
- For option (b) (1, 1):
- f(1) = -3(1-1) + 2 = -3(0) + 2 = 0 + 2 = 2 which is not equal to 1. So, (1, 1) does not lie on the graph.
- For option (c) (0, 0):
- f(0) = -3(0-1) + 2 = -3(-1) + 2 = 3 + 2 = 5 which is not equal to 0. So, (0, 0) does not lie on the graph.
- For option (d) (-1, 2):
- f(-1) = -3(-1-1) + 2 = -3(-2) + 2 = 6 + 2 = 8 which is not equal to 2. So, (-1, 2) does not lie on the graph.
Therefore, none of the given ordered pairs lie on the graph of the exponential function f(x) = -3(x-1) + 2.