Question

A ball is rolling across a table with a horizontal velocity of 2m/s. It rolls off a table that's 2m tall. How far does the ball land away from the table (Δx)?

a) 1.26 m Away
b) 4.13 m Away
c) 0.98 m Away
d) 3.45 m Away

Answer 1

To calculate the distance the ball lands away from the table, we can use the equations of motion. First, find the time it takes for the ball to fall from the table. Then, calculate the horizontal distance the ball travels using the horizontal velocity and the time.

Step-by-step explanation:

To calculate the distance the ball lands away from the table, we can use the equations of motion. First, we need to find the time it takes for the ball to fall from the table.

We can use the equation:

d = vit + 1/2at^2

Since the initial vertical velocity is 0, the equation simplifies to:

d = 1/2at^2

Plugging in the acceleration due to gravity (9.8 m/s^2) and solving for t, we find that it takes approximately 0.64 seconds for the ball to fall.

Now, we can find the horizontal distance the ball travels by using the equation:

d = vxt

Plugging in the horizontal velocity (2 m/s) and the time (0.64 seconds), we find that the ball lands approximately 1.28 meters away from the table.