Question

Jim has 44 coins using only nickels and dimes totaling $2.95. How many of each coin does he have?

Answer 1

Jim has 29 nickels and 15 dimes.

Step-by-step explanation:

To solve this problem, we can use a system of equations.

Let x represent the number of nickels and y represent the number of dimes.

We can set up two equations:

We can solve this system of equations to find the values of x and y.

Multiplying the second equation by 5, we get:

5x + 5y = 220

Now we can subtract the second equation from the first equation:

(5x + 10y) - (5x + 5y) = 295 - 220

Which simplifies to:

5y = 75

Dividing both sides by 5, we get:

y = 15

Substituting this value of y back into the second equation, we can solve for x:

x + 15 = 44

x = 29

Therefore, Jim has 29 nickels and 15 dimes.