Final answer:
36.04 grams of water reacts to form 3.0 g of hydrogen gas and 24.0 g of oxygen gas during electrolysis.
Step-by-step explanation:
The balanced equation for the reaction of water (H2O) to form hydrogen gas (H2) and oxygen gas (O2) during electrolysis is:
2 H2O(l) → 2 H2(g) + O2(g)
To determine how much water reacts to form 3.0 g of hydrogen gas and 24.0 g of oxygen gas, we need to calculate the amount of water in grams using the molar masses of hydrogen and oxygen:
2 moles of hydrogen gas (H2) = 2 x 2.02 g = 4.04 g
1 mole of oxygen gas (O2) = 32.0 g
Therefore, the total mass of water (H2O) that reacts is: 4.04 g + 32.0 g = 36.04 g
So, 36.04 grams of water reacts to form 3.0 g of hydrogen gas and 24.0 g of oxygen gas during electrolysis.