Evaluate the polynomial when (a) x = 0 and (b)x =1 (x3+6x2-14)?

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asked May 6, 2024 168k views

1 Answer

HussoM · Answer 1 · 2024-05-09T21:11:26+0000

To evaluate the polynomial x^3+6x^2-14 when (a) x = 0 and (b) x = 1, substitute the values of x into the polynomial and simplify.

To evaluate the polynomial x^3+6x^2-14 when (a) x = 0 and (b) x = 1, we substitute the values of x into the polynomial and simplify.

(a) x = 0: 0^3 + 6(0)^2 - 14 = -14

(b) x = 1: 1^3 + 6(1)^2 - 14 = -7