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Write an equation for the parabola that has a vertex of (-1, 8) and goes through the point of (2, -10)?

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Final answer:

The equation of the parabola with a vertex at (-1, 8) that passes through (2, -10) is y = -2(x + 1)^2 + 8.

Step-by-step explanation:

To write the equation for a parabola with a given vertex and a point it passes through, we use the vertex form of a parabola's equation, which is:

y = a(x - h)2 + k

where (h, k) is the vertex of the parabola. In this case, the vertex is (-1, 8). So the equation starts as:

y = a(x + 1)2 + 8

We need to determine the value of a. Since the parabola passes through the point (2, -10), we can substitute x with 2 and y with -10 to find a:

-10 = a(2 + 1)2 + 8
-10 = a(3)2 + 8
-10 = 9a + 8
-18 = 9a
a = -2

The value of a is -2. Thus, the equation of the parabola is:

y = -2(x + 1)2 + 8

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