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Graph \[y=\dfrac{5}{3}x-9\].

User Jerry G
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Answer: A straight line through (0,-9) and (3,-4)

The graph is shown below.

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Step-by-step explanation

I'll show two methods.

Method 1


y=(5)/(3)x-9 is the same as y = (5/3)x - 9 when writing it out on a computer keyboard.

The equation y = (5/3)x - 9 is of the form y = mx+b

  • m = 5/3 = slope
  • b = -9 = y intercept

The y intercept is our anchor point. Always start here. It represents the location (0,-9).

From that anchor, move 5 units up and 3 units right. This "up 5, right 3" motion is directly from the slope 5/3. Recall that slope = rise/run.

Start at (0,-9) and follow the "up 5, right 3" pathway to arrive at (3,-4)

Then plot the two points (0,-9) and (3,-4). The last step is to draw a straight line through them. See the graph below. GeoGebra was used to make the graph. Desmos is another option.

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Method 2

To plot a line, we need 2 points on it. Each point is of the format (x,y)

Select random values for x to find their corresponding y coordinates.

For instance, if x = 0, then,

y = (5/3)x - 9

y = (5/3)*0 - 9

y = 0 - 9

y = -9

The input x = 0 leads to the output y = -9

We have the point (0,-9) that was mentioned in the previous section. It's the y intercept.

Repeat the process with another x value. You could pick x = 1, but it leads to messy fractions.

It's better to pick x = 3 since it cancels with the denominator.

If x = 3, then,

y = (5/3)x - 9

y = (5/3)*3 - 9

y = 5 - 9

y = -4

We arrive at (3,-4) that was mentioned in the previous section.

And also mentioned previously is that we plot the two points and then draw a straight line through them.

See the graph below.

Graph \[y=\dfrac{5}{3}x-9\].-example-1
User Ejoerns
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9.0k points

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