203k views
0 votes
In a dog show, how many ways can four Pomeranians, five golden retrievers, two Great Pyrenees, and six English terriers line up in front of the judges if the dogs of the same breed are considered identical? In how many different ways can three dogs win first, second, and third place?

User Brm
by
7.7k points

1 Answer

4 votes

Final answer:

To find the number of ways the dogs can line up in front of the judges, we can use the concept of permutations. We need to calculate the number of ways to arrange the different breeds of dogs. To calculate the number of different ways for three dogs to win first, second, and third place, we can use the concept of combinations.

Step-by-step explanation:

To find the number of ways the dogs can line up in front of the judges, we can use the concept of permutations. Since dogs of the same breed are considered identical, we need to calculate the number of ways to arrange the different breeds of dogs.

First, we calculate the number of ways to arrange the Pomeranians, golden retrievers, Great Pyrenees, and English terriers separately. Since there are 4 Pomeranians, 5 golden retrievers, 2 Great Pyrenees, and 6 English terriers, we have:

Pomeranians: 4!

Golden Retrievers: 5!

Great Pyrenees: 2!

English Terriers: 6!

Then, we multiply these values together to get the total number of ways to arrange the dogs:

Total number of ways = 4! * 5! * 2! * 6!

To calculate the number of different ways for three dogs to win first, second, and third place, we can use the concept of combinations. We have a total of 17 dogs, so the number of combinations of 3 dogs is:

Number of combinations = 17 choose 3 = 17! / (3! * (17-3)!)

After calculating the above values, you will get the answer to the question.

User Tjeubaoit
by
7.6k points