Question

A playing field for the Indoor Football League has a length 26yd longer than its width. The perimeter of the rectangular field is 164yd. Find the length and width of the field.

Answer 1

The width of the playing field is 28 yards and the length is 54 yards.

Step-by-step explanation:

Let's assume that the width of the playing field is x yards. According to the given information, the length of the playing field is 26 yards longer than its width, which means the length is x + 26 yards.

The perimeter of a rectangle is given by the formula: P = 2(l + w), where P is the perimeter, l is the length, and w is the width. Substituting the given values, we have:

164 = 2(x + 26 + x)

164 = 2(2x + 26)

164 = 4x + 52

4x = 164 - 52

4x = 112

x = 28

Therefore, the width of the playing field is 28 yards and the length is 28 + 26 = 54 yards.