Question

The 0.63 kg ball leaves the players hand at 12 m/s. With the information provided, determine the height that the ball will go before coming back down?

Answer 1

To determine the height that the ball will go before coming back down, we can use the kinematic equation for vertical motion. Therefore, the ball will go approximately 7.35 meters before coming back down.

Step-by-step explanation:

To determine the height that the ball will go before coming back down, we can use the kinematic equation for vertical motion:

h = (vy2 - uy2) / (2g)

Where:

• h is the height
• vy is the final vertical velocity
• uy is the initial vertical velocity
• g is the acceleration due to gravity (-9.8 m/s2)

Given that the ball leaves the player's hand with an initial vertical velocity of 12 m/s, we can substitute the values into the equation:

h = (0 - 122) / (2 * -9.8)

Simplifying the equation:

h = 144 / 19.6

h ≈ 7.35 meters

Therefore, the ball will go approximately 7.35 meters before coming back down.