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If I have a gas at 20.0 mL and 33.0 C and raise the temperature to 57.0 C, what is the new volume?

A) 34.55 mL
B) 34.5 mL
C) 45.6 mL
D) 45.55 mL

User Ariefbayu
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1 Answer

7 votes

Final answer:

The question involves using Charles's Law to find the new volume of gas when temperature changes. None of the given answer choices match the calculated volume of 21.6 mL, suggesting there may be an error in the question or answer options.

Step-by-step explanation:

The question about the change in volume of a gas with a change in temperature is an application of Charles's Law. Charles's Law states that the volume of a gas is directly proportional to its temperature when the pressure is held constant. To find the new volume when the temperature changes, we use the formula:

V1/T1 = V2/T2,

where V1 is the initial volume, T1 is the initial temperature in kelvins, V2 is the final volume, and T2 is the final temperature in kelvins. Since the problem provides temperatures in degrees Celsius, we first convert them to kelvins by adding 273.15.

The initial temperature is 33.0 C, which is 306.15 K (33.0 + 273.15), and the final temperature is 57.0 C, which is 330.15 K (57.0 + 273.15). Plugging the initial volume and temperatures into the formula:

(20.0 mL / 306.15 K) = (V2 / 330.15 K),

we solve for V2:

V2 = (20.0 mL * 330.15 K) / 306.15 K,

V2 ≈ 21.6 mL.

However, since none of the given answer options matches this result, it is likely that there has been a miscalculation or misunderstanding in the question.

User KhaoulaAtallah
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8.5k points