Question

When a resistor (R) is connected to an electric cell, electric current intensity (I) passes through it, and when another resistor of value fraction numerator R over denominator 6 end fraction is connected with the first in parallel, the electric current intensity increased 2.5 times. Calculate the internal resistance of the electric cell in terms of R.

Answer 1

To calculate the internal resistance of the electric cell in terms of R, we use the equation I = E/(R + r). When a second resistor of value R/6 is connected in parallel, the current intensity increases 2.5 times. Solving the equation, we find that the internal resistance r is equal to R/2.5.

Step-by-step explanation:

To calculate the internal resistance of the electric cell in terms of R, we first need to understand the relationship between current intensity and resistance. When a resistor R is connected to an electric cell, the current intensity passing through it is given by I = E/(R + r), where E is the electromotive force of the cell and r is the internal resistance of the cell.

When a second resistor of value R/6 is connected in parallel with the first resistor, the current intensity increases 2.5 times. We can write this as (E/(R + r))/(R/(6R)) = 2.5 and simplify to find the value of r in terms of R.

By solving this equation, we find that the internal resistance r of the electric cell is equal to R/2.5.