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Eight times the sum of a number and 18 is at most -26. Use the variable b for the unknown number.

User Zzheads
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Final answer:

To solve the inequality 8 times the sum of a number and 18 being at most -26, we translate it into the inequality 8(b + 18) ≤ -26, simplify to 8b ≤ -170, and solve to find b ≤ -21.25.

Step-by-step explanation:

The student's question involves creating an inequality to represent the given situation. We use the variable b for the unknown number. The inequality is written as: 8(b + 18) ≤ -26. To solve for b, we start by distributing the 8:

8b + 144 ≤ -26

Next, we subtract 144 from both sides:

8b ≤ -170

And finally, we divide both sides by 8 to isolate b:

b ≤ -21.25

This means that the number b must be less than or equal to -21.25 for the inequality to hold true.

User Malavika
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