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There are 25 townhomes in the Alief Community subdivision.

Company A provides water to 1/5 of the townhomes.
Company B provides water to 9/15 of the townhomes.
Company C provides water to the remaining townhomes.
In this subdivision, company C provides water to how many houses?

1 Answer

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Final answer:

In the Alief Community subdivision of 25 townhomes, Company C provides water to 5 townhomes after subtracting the number served by Company A and Company B.

Step-by-step explanation:

In the Alief Community subdivision, which has 25 townhomes, we need to determine how many townhomes are served by Company C. Company A serves 1/5 of the homes, which is 25 homes × (1/5) = 5 homes. Company B provides water to 9/15 of the homes, but this fraction simplifies to 3/5 when divided by 3. So, Company B serves 25 homes × (3/5) = 15 homes. To find out how many homes Company C serves, we subtract the number of homes served by Company A and B from the total number of homes: 25 - (5 + 15) = 25 - 20 = 5 homes. Therefore, Company C provides water to 5 townhomes in the subdivision.

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