Final answer:
The ball's instantaneous velocity after 6 seconds is 58.86 m/s. At 5 seconds, the ball has traveled 122.625 m. It takes approximately 17.53 seconds for the ball to reach the ground from 1500 meters.
Step-by-step explanation:
To find the instantaneous velocity of the ball after 6 seconds when dropped from rest, we use the equation of motion v = gt, where g is the acceleration due to gravity (approximately 9.81 m/s2) and t is the time in seconds. After 6 seconds, the velocity would be v = 9.81 m/s2 * 6 s = 58.86 m/s.
To calculate the distance traveled by the ball at a time 5 seconds, we use the equation s = (1/2)gt2. Thus, the distance would be s = (1/2) * 9.81 m/s2 * (5 s)2 = 122.625 m.
For the total time to reach the ground from a height of 1500 meters, we can use the equation s = (1/2)gt2, solving for t. Rearranging this for t, we get t = sqrt(2s/g), which gives us t = sqrt(2 * 1500 m / 9.81 m/s2) ≈ 17.53 seconds.