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Lucia is riding her Go-cart at 10 meters per second. Right after beginning her journey, she accelerates to 4 meters per second in 3 seconds. Assuming she started 5 meters behind the starting line, how far in front of the starting line did she end up (after those 10 seconds)?

User Briddums
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Final answer:

Lucia ended up 53 meters in front of the starting line after those 10 seconds of riding her Go-cart.

Step-by-step explanation:

Lucia's initial velocity is 10 m/s. After 3 seconds, she accelerates to 4 m/s. From this point on, she continues at a constant velocity of 4 m/s for the remaining 7 seconds. Therefore, she covers a total distance of 4 m/s * 7 s = 28 meters during this period.

During the first 3 seconds, she covers a distance of 10 m/s * 3 s = 30 meters at her initial velocity. Adding this to the distance covered during the constant velocity period, we get a total distance of 30 meters + 28 meters = 58 meters in front of the starting line.

However, since Lucia started 5 meters behind the starting line, we need to subtract this distance to find out how far in front of the starting line she ended up. Therefore, she ended up 53 meters in front of the starting line.

User The Berserker
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