Question

The price, y, for a taxi ride of x miles can be modeled using a linear function. The driver charges a fixed cost of $2.50 plus an additional cost of $2.70 per mile for a maximum of 35 miles. For one taxi ride, what is the range of the function for this situation?

A) 0 ≤ y ≤ 97
B) 0 ≤ y ≤ 90.20
C) 0 ≤ y ≤ 2.50
D) 0 ≤ y ≤ 35

Answer 1

The range of the linear function that models the price of a taxi ride with a fixed cost and additional cost per mile is 0 ≤ y ≤ 97.

Step-by-step explanation:

To find the range of the linear function that models the price of a taxi ride, we need to determine the maximum and minimum possible values for y. In this case, the fixed cost is $2.50, and the additional cost per mile is $2.70. To find the maximum value of y, we need to consider the scenario where the taxi ride is for the maximum number of miles, which is 35 miles. Therefore, the maximum value of y is $2.50 + ($2.70 * 35) = $2.50 + $94.50 = $97. To find the minimum value of y, we need to consider the scenario where the taxi ride is for 0 miles. Therefore, the minimum value of y is $2.50 + ($2.70 * 0) = $2.50. Therefore, the range of the function is 0 ≤ y ≤ 97.

Answer 2

Bbbbb option is absolutely right