Question

When glucose is consumed, it reacts with oxygen in the body to produce carbon dioxide, water, and energy. How many grams of carbon dioxide would be produced if 45 g of C6H12O6 completely reacted with oxygen?

A) 1.89 g
B) 669.11 g
C) 1.5 g
D) None of the Above

Answer 1

To calculate the grams of carbon dioxide produced when glucose reacts with oxygen, we use the balanced chemical equation and the molar masses of the compounds involved. By finding the number of moles of glucose and the mole ratio with carbon dioxide, we can determine the number of moles and the mass of carbon dioxide produced. The mass of carbon dioxide produced is 65.77 g.

Step-by-step explanation:

To calculate the grams of carbon dioxide produced when glucose reacts with oxygen, we need to use the balanced chemical equation and the molar masses of the compounds involved. The balanced equation is: C6H12O6 + 6O2 -> 6CO2 + 6H2O. The molar mass of glucose is 180.16 g/mol and the molar mass of carbon dioxide is 44.01 g/mol.

First, we find the number of moles of glucose in 45 g using the formula: moles = mass/molar mass. Substituting the values, moles of glucose = 45 g / 180.16 g/mol = 0.249 mol. Since the mole ratio between glucose and carbon dioxide is 1:6, the number of moles of carbon dioxide produced is: 0.249 mol x 6 = 1.494 mol. Finally, we find the mass of carbon dioxide produced using the formula: mass = moles x molar mass. Substituting the values, mass of carbon dioxide = 1.494 mol x 44.01 g/mol = 65.77 g.