Final answer:
To find three odd numbers whose product is 3315, use prime factorization to break down 3315 into factors. The odd numbers obtained are 3, 5, and 221 (which is the product of 13 and 17, two odd primes).
Step-by-step explanation:
Finding three odd numbers whose product is 3315 requires prime factorization. To find the factors, we start by dividing 3315 by the smallest prime number possible, which is 3 (because 3315 ends with a 5, it is not divisible by 2, and the sum of its digits is divisible by 3, suggesting it's divisible by 3).
After dividing 3315 by 3, we get 1105. The next step is to divide 1105 by 3 again, which gives us 368.33, indicating that 3 is no longer a divisor. Instead, we look at the next smallest prime number, which is 5. Dividing 1105 by 5, we get 221, which is no longer divisible by 5. After testing more divisors, we find that 221 can be divided by 13, which gives us 17. So, 1105 is 5 * 13 * 17, and since all these factors are prime, the factorization is complete.
Therefore, the three odd numbers whose product equals 3315 are 3, 5, and 221, where 221 is further factorable into 13 and 17. Hence, the numbers are 3, 5, and 13 x 17. The sequence of three odd numbers would then be 3, 5, and 221 (since 221 is the product of two odd primes, it is also odd).