Final answer:
When chlorine gas reacts with aqueous Sodium Bromide, it produces aqueous Sodium Chloride and Bromine gas. To determine the number of liters of Bromine gas produced, calculate the moles of Sodium Bromide used and use the balanced chemical equation to find the moles of Bromine gas produced. Finally, use the ideal gas law to convert the moles of gas to liters.
Step-by-step explanation:
In the reaction between chlorine gas and aqueous Sodium Bromide, chlorine gas replaces bromine in the compound to produce aqueous sodium chloride and elemental bromine. The balanced chemical equation for this reaction is:
Cl₂ (g) + 2NaBr (aq) → 2NaCl (aq) + Br₂ (1)
To determine the amount of bromine gas produced, we need to use the given mass of sodium bromide. First, calculate the molar mass of sodium bromide (NaBr):
Molar mass of NaBr = (1 mol of Na x atomic mass of Na) + (1 mol of Br x atomic mass of Br)
Next, use the molar mass to convert the given mass of sodium bromide to moles:
Moles of NaBr = given mass of NaBr / molar mass of NaBr
Finally, use the balanced equation to determine the moles of bromine gas produced, and then convert to liters using the ideal gas law.