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What is the equation of a line parallel to y= -3x+4 that goes through the point (5, 2)?

User Cardoso
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1 Answer

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Final answer:

The equation of the line parallel to y = -3x + 4 and passing through the point (5, 2) is y = -3x + 17. This is determined by using the same slope as the original line and solving for the y-intercept using the coordinates of the given point.

Step-by-step explanation:

The question asks for the equation of a line that is parallel to the given line y = -3x + 4 and passes through the point (5, 2). To find this line, we must use the fact that parallel lines have the same slope. Since the given line has a slope of -3, our new line will also have a slope of -3.

The general form of the equation of a line is y = mx + b, where m is the slope and b is the y-intercept. In this scenario, we already know that m = -3 for our new line. Now, we need to find the y-intercept b by plugging in the coordinates of the given point (x=5, y=2) from which our line should pass through:

y = mx + b
2 = (-3)(5) + b
2 = -15 + b
b = 17

Thus, the equation of our parallel line is y = -3x + 17.

User Krzysztof Przygoda
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