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C₅H₈0 with HONH₂ in the presence of H+ gives?

User Quayshawn
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Final answer:

When C5H8O reacts with hydroxylamine (HONH2) in the presence of H+, it forms an oxime as the organic product. The exact structure of the oxime depends on the specific structure of the starting ketone or aldehyde.

Step-by-step explanation:

The question involves a reaction between a compound with the formula C5H8O and hydroxylamine (HONH2) in the presence of acid (H+). This type of reaction commonly leads to the formation of an oxime. However, the exact structure of the starting compound C5H8O is not specified, so it's difficult to provide a detailed mechanism or the exact structure of the product. Typically, the carbonyl group of an aldehyde or ketone reacts with hydroxylamine in an acid-catalyzed reaction to form the corresponding oxime.

For example, if C5H8O represents a ketone or aldehyde, the general reaction with hydroxylamine would be:

  • C5H8O + HONH2 → C5H8ONH + H2O

This forms an oxime (C5H8ONH) as the organic product, along with water. Oximes are characterized by a C=N-OH functional group.

User Anne Gunn
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