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A girl walks 30meters north. Then she walks 29meters south. What is the girl's distance described in this problem?

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Final answer:

The girl's distance described in this problem is 59 meters.

Step-by-step explanation:

The girl's distance described in this problem can be found by considering the displacements separately and then finding the resultant displacement.

  1. The girl walks 30 meters north. This is a displacement of +30 meters in the north direction.
  2. Then, she walks 29 meters south. This is a displacement of -29 meters in the south direction.

To find the girl's total distance, we must consider the magnitudes of the displacements, not their directions. Therefore, we add the magnitudes: 30 + 29 = 59 meters. So, the girl's distance described in this problem is 59 meters.

User Peter Boone
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