Final answer:
To float a toy car weighing 112 grams, it would take a volume of water that is equal to its weight, which is 0.112 liters.
Step-by-step explanation:
To determine the volume of water needed to float a toy car, we can use Archimedes' Principle, which states that the buoyant force exerted on an object submerged in a fluid is equal to the weight of the fluid displaced by the object.
The weight of the toy car is 112 grams, and we need to find the volume of water that has an equal weight. Since the density of water is 1 gram/mL, the volume of water needed is 112 mL or 0.112 liters.