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If a cart with a mass of 0.5 kg decreases its velocity by 0.15 m/s during a 2.25 s time period due to friction, what was the force of friction acting on the cart?

User GGalizzi
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Final answer:

To calculate the force of friction acting on a cart that slows down due to friction, divide the change in velocity by time to get acceleration, then multiply by the mass of the cart. For a 0.5 kg cart slowing down by 0.15 m/s over 2.25 s, the force of friction is -0.03335 N.

Step-by-step explanation:

To find the force of friction acting on a cart that has decreased its velocity during a certain time period, we want to use the concept of acceleration and Newton's second law of motion. The acceleration a can be calculated by the change in velocity Δv divided by the time t, which is a = Δv / t. Then, using Newton's second law, F = ma, where F is the force, m is the mass, and a is the acceleration, we can determine the force of friction. Here, the mass of the cart m is 0.5 kg, the change in velocity Δv is -0.15 m/s, and the time t is 2.25 s. So, acceleration a is -0.15 m/s / 2.25 s = -0.0667 m/s². The negative sign indicates that this is a deceleration. Finally, the force of friction F is (0.5 kg)(-0.0667 m/s²) = -0.03335 N. The negative sign here indicates that the friction force is opposing the initial direction of motion.

User Pankaj Jatav
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