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Find the average atomic mass for Boron (B) if 19.9% of B atoms are Boron-10 and 80.1% are Boron-11.

User Rsimp
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Final answer:

The average atomic mass for Boron is 10.801 amu, calculated by multiplying the abundance of each isotope by its mass and summing them up.

Step-by-step explanation:

The average atomic mass for Boron can be calculated using the percentages and masses of its isotopes. In this case, 19.9% of Boron atoms are Boron-10, which has a mass of 10 amu, and 80.1% are Boron-11, which has a mass of 11 amu. To find the average atomic mass, you multiply the abundance (percentage) of each isotope by its mass and then sum them up.

  1. Multiply 19.9% by 10 amu: (0.199)(10) = 1.99 amu
  2. Multiply 80.1% by 11 amu: (0.801)(11) = 8.811 amu
  3. Add these two values together: 1.99 amu + 8.811 amu = 10.801 amu

Therefore, the average atomic mass for Boron is 10.801 amu.

User Edu Wass
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