Final answer:
The final velocity of Sunny and the other star after the collision would be 3 m/s, calculated using the conservation of momentum.
Step-by-step explanation:
The question concerns a problem in physics related to conservation of momentum, specifically in a scenario involving an inelastic collision. In such a collision, two objects stick together after impact, and the mass of Sunny, the mascot, and the other star combined would equal their total mass. The velocity of these two masses after the collision can be found by applying the law of conservation of momentum, which states that the total momentum before the collision equals the total momentum after the collision when no external forces are involved.
The formula to use is:
m1 * v1 + m2 * v2 = (m1 + m2) * v'
Where:
- m1 is the mass of the first object (Sunny)
- v1 is the velocity of the first object (Sunny)
- m2 is the mass of the second object (the other star)
- v2 is the velocity of the second object (initially at rest, so 0 m/s for the other star)
- v' is the final velocity of both objects stuck together
Assuming Sunny has the same mass as the other star (as not specified, we'll consider m1 = m2 = 600 kg for the purpose of this answer), and knowing that v1 = 6 m/s while v2 = 0 m/s (the other star is at rest before the collision), the conservation of momentum can be solved for to find the final velocity v' as follows:
600 kg * 6 m/s + 600 kg * 0 m/s = (600 kg + 600 kg) * v'
v' = (3600 kg*m/s) / (1200 kg)
v' = 3 m/s
Therefore, the combined mass of Sunny and the other star would move at a velocity of 3 m/s after the collision.