Question

If a container has a volume of 38 mL and a pressure of 0.54 atm, what will the pressure be if the volume decreases to 26 mL?

A) 0.74 atm
B) 0.92 atm
C) 0.58 atm
D) 1.46 atm

Answer 1

According to Boyle's Law, the pressure and volume of a gas are inversely proportional. By plugging in the given values into Boyle's Law equation (P1V1 = P2V2) and solving for P2, we find that the pressure will be 0.79 atm when the volume decreases to 26 mL.

Step-by-step explanation:

To solve this problem, we can use Boyle's Law, which states that the pressure and volume of a gas are inversely proportional at constant temperature and amount of gas. Mathematically, this can be represented as P1V1 = P2V2. Using this equation, we can plug in the given values to find the final pressure.

Given:

1. P1 = 0.54 atm
2. V1 = 38 mL
3. V2 = 26 mL

Using the formula:

(P1)(V1) = (P2)(V2)

Plugging in the given values:

(0.54 atm)(38 mL) = (P2)(26 mL)

Simplifying the equation:

20.52 atm·mL = (P2)(26 mL)

Dividing both sides of the equation by 26 mL:

P2 = 0.79 atm

Therefore, the pressure will be 0.79 atm if the volume decreases to 26 mL.