Question

Mr. Hayes' classroom has a height of 60 inches and a base of 80 inches. what is the area of his classroom?​

Answer 1

The area of Mr. Hayes' classroom is 4800 square inches, which converts to approximately 33.33 square feet after dividing by 144, the number of square inches in one square foot.

Step-by-step explanation:

Mr. Hayes' classroom dimensions are provided in inches, with a height (presumably the length of one of the walls) of 60 inches and a base (or width of the opposite wall) of 80 inches. To calculate the area of the classroom, which is a rectangle, we multiply the length by the width.

Therefore, the area is 60 inches * 80 inches = 4800 square inches. However, since the area of a room is typically given in square feet, we can convert the area to square feet. There are 144 square inches in one square foot, so 4800 square inches is equal to 4800 / 144 = 33.33 square feet.

Thus, the area of Mr. Hayes' classroom is approximately 33.33 square feet.

Answer 2

• 4800 square inches

Step-by-step explanation:

To find the area of Mr. Hayes' classroom,

let's use the formula for the area of a rectangle:

`\boxed{\sf Area = length * width}`

Given :

→ Height of the classroom : 60 inches which corresponds to the length.

→ Base of the classroom : 80 inches, which corresponds to the width.

Now, let's calculate the area:

Formula of area:

length × width

• Area = 60 × 80

• Area = 4800

Therefore, the area of Mr. Hayes' classroom is 4800 square inches.

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