Question

Consider the cubic function y=x+ 2x2 - 8x.

(a) Algebraically determine the zeroes of this cubic function.

Answer 1

The zeros of the cubic function y = x + 2x^2 - 8x can be determined algebraically using the quadratic formula.

Step-by-step explanation:

This expression is a quadratic equation of the form ax² + bx + c = 0, where the constants are a = 1, b = 2, and c = -8. To determine the zeros, we can use the quadratic formula: x = (-b ± √(b^2 - 4ac)) / (2a). Plugging in the values, we get: x = (-2 ± √(2^2 - 4(1)(-8))) / (2(1)). Simplifying further, we have: x = (-2 ± √(52)) / 2. This gives us two possible values for x: x = (-2 + √52) / 2 and x = (-2 - √52) / 2.