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What is the equation of the line through (2, 3) and (0, -1)?

A) y= 2x + 1
B) y= 2x - 1
C) y=-2x + 1
D) y=-2x-1

User Rzar
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1 Answer

5 votes

Final answer:

The equation of the line passing through the points (2, 3) and (0, -1) is y = 2x - 1. After finding the slope using the rise over run method, the y-intercept was calculated using one of the points and the slope value.

Step-by-step explanation:

To find the equation of the line that passes through the points (2, 3) and (0, -1), we need to determine the slope (m) and y-intercept (b) of the line using the formula y = mx + b. The slope can be found by the formula (y2 - y1) / (x2 - x1), which represents rise over run. Using the given points:

  • m = (3 - (-1)) / (2 - 0) = 4 / 2 = 2

With a slope of 2, we can plug one of the points into the slope-intercept form to solve for b:

  • 3 = 2(2) + b
  • 3 = 4 + b
  • b = 3 - 4
  • b = -1

Now, we have the slope m = 2 and y-intercept b = -1. Therefore, the equation of the line is y = 2x - 1, which corresponds to option B.

User Jmpcm
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