Question

A stone is projected at an angle 30 to the horizontal from the top of a tower of height 100m and it hit the ground at point Q .if initial velocity os 100. calculate, Time taken to reach this height ,maximum height, horizontal distance from the foot of the tower to the point Q .( g-10ms¹)​

Answer 1

The time taken to reach the maximum height is 5 seconds, the maximum height is 250 meters, and the horizontal distance is 250 meters.

Step-by-step explanation:

To find the time taken to reach the maximum height, we can use the formula:

T = V * sin(theta) / g

where T is the time, V is the initial velocity, theta is the launch angle, and g is the acceleration due to gravity. In this case, V = 100 m/s and theta = 30 degrees. Plugging these values into the formula gives:

T = 100 * sin(30) / 10 = 5 seconds

To find the maximum height, we can use the formula:

H = V^2 * sin^2(theta) / (2 * g)

where H is the maximum height. Plugging in the values:

H = 100^2 * sin^2(30) / (2 * 10) = 250 meters

To find the horizontal distance, we can use the formula:

D = V * cos(theta) * T

where D is the horizontal distance. Plugging in the values:

D = 100 * cos(30) * 5 = 250 meters