Question

What is the output?

public static void main(String[] args) {
for (int i = 0; i < 3; ++i) {
System.out.print(i);
} System.out.print(i);
}

Answer 1

The Java code snippet involves a for-loop printing numbers 0 to 2. However, there is an error; the variable 'i' is used outside its scope, resulting in a compile-time error.

Step-by-step explanation:

The code provided is a Java program trying to print the values of the local variable i within a for loop and once outside of it. The output will be:

012

However, the program contains an error. The second System.out.print(i); statement is outside of the loop, which means it is attempting to access i outside of its scope. i is only defined within the for-loop, so there will be a compile-time error when trying to print it outside of the loop. To resolve this, i should only be used within its scope