Question

Consider an 8x8 array for a board game:

int[][]board = new int[8][8];

Using two nested loops, initialize the board so that zeros and ones alternate as on a checkboard:

0 1 0 1 0 1 0 1

1 0 1 0 1 0 1 0

0 1 0 1 0 1 0 1

....

1 0 1 0 1 0 1 0

Answer 1

To initialize the board array so that zeros and ones alternate as on a checkerboard, you can use two nested loops. The code will set the values of the board array to alternate between zeros and ones, creating a checkerboard pattern.

Step-by-step explanation:

To initialize the board array so that zeros and ones alternate as on a checkerboard, you can use two nested loops. The outer loop iterates through the rows of the array, and the inner loop iterates through the columns. Inside the inner loop, you can use the modulo operator to determine whether to assign a zero or a one to each element of the array, based on the row and column indices.

int[][] board = new int[8][8];
for (int row = 0; row < 8; row++) {
for (int col = 0; col < 8; col++) {
board[row][col] = (row + col) % 2;
}
}

This code will set the values of the board array to alternate between zeros and ones, creating a checkerboard pattern.