The charge that will flow from the battery is \(1.12 \times 10^{-7} \, \text{C}\).
The charge (\(Q\)) on a capacitor is given by the formula:
\[ Q = C \cdot V \]
where:
\(Q\) = charge on the capacitor,
\(C\) = capacitance of the capacitor,
\(V\) = voltage across the capacitor.
Given:
\(C = 3500 \, \text{pF} = 3.5 \times 10^{-9} \, \text{F}\) (converting from picofarads to farads),
\(V = 32 \, \text{V}\).
\[ Q = (3.5 \times 10^{-9} \, \text{F}) \times (32 \, \text{V}) \]
\[ Q = 1.12 \times 10^{-7} \, \text{C} \]
Therefore, the charge that will flow from the battery is \(1.12 \times 10^{-7} \, \text{C}\).