Question

charge q1=9.5 nc is located at the coordinate system origin, while charge q2=1.5 nc is located at (a,0) , where a=1.1 m . the point p has coordinates (a,b) , where b=3.4 m .?

Answer 1

The electric potential at point P can be calculated using the formula V = k*q/r, where V is the potential, k is Coulomb's constant, q is the charge, and r is the distance between the charges.

Step-by-step explanation:

To calculate the electric potential at point P, we can use the formula:

V = k*q/r

Where V is the potential, k is the Coulomb's constant, q is the charge, and r is the distance between the charges.

In this case, q1 is located at the origin and q2 is located at (a,0).

So, the potential at point P can be calculated as:

V = k*q1/√((a - a)^2 + (b - 0)^2)

Since the x-coordinate of point P is the same as the x-coordinate of q2, the distance in the numerator becomes 0. Therefore, the denominator simplifies to b.

So the potential at point P is:

V = k*q1/b