Question

To sterilize a 53.0 g glass baby bottle, we must raise its temperature from 23.0°C to 94.0°C. How much heat transfer (in J) is required?

Answer 1

The heat transfer required to raise the temperature of a 53.0 g glass baby bottle from 23.0°C to 94.0°C is approximately 3163 Joules.

Step-by-step explanation:

To calculate the heat transfer required to sterilize a glass baby bottle, we can use the specific heat capacity of glass and the formula:

Q = mcΔT

Where:

• Q is the heat energy in joules (J)
• m is the mass of the bottle in kilograms (kg)
• c is the specific heat capacity (For glass, it is approximately 0.84 J/g°C)
• ΔT is the change in temperature in degrees Celsius (°C)

Firstly, convert the mass from grams to kilograms:

53.0 g = 0.053 kg

Then, substitute the known values into the formula:

Q = (0.053 kg)(0.84 J/g°C)(94.0°C - 23.0°C)

Q = (0.053 kg)(0.84 J/g°C)(71.0°C)

Q = (0.053 kg)(59.64 J/°C)

Q = 3.16092 J

After running the calculation, the heat transfer required to sterilize the glass baby bottle is approximately 3163 Joules.