Question

The suspended 2.3 kg mass on the right is moving up, the 2.7 kg mass slides down the ramp, and the suspended 7.1 kg mass on the left is moving down. The coefficient of friction between the block and the ramp is 0.11. The acceleration of the gravity ramp is 0.11. Pulleys are massless and frictionless. What is the acceleration of the three-block system? Answer in units of m/s². What is the tension in the cord connected to the 2.3 kg block? Answer in units of N. What is the tension in the cord connected to the 7.1 kg block? Answer in units of N.

Answer 1

To find the acceleration of the three-block system, analyze the forces acting on each block. Equate the net force on each block to its mass times its acceleration to find the acceleration of the system. Solve for the tension in the cords connected to the 2.3 kg block and the 7.1 kg block by equating the net force on each block to its mass times its acceleration.

Step-by-step explanation:

To find the acceleration of the three-block system, we need to analyze the forces acting on each block. The 2.3 kg block is suspended and moving up, so the tension in the cord connected to it is pulling it upwards. The 2.7 kg block is sliding down the ramp, so it experiences a force due to gravity and a frictional force. The 7.1 kg block is suspended and moving down, so the tension in the cord connected to it is pulling it downwards.

The acceleration of the system can be found by equating the net force on each block to its mass times its acceleration. Using this approach, we can solve for the acceleration of the system.

The tension in the cord connected to the 2.3 kg block can be found by equating the net force on the block to its mass times its acceleration. With this information, we can solve for the tension in the cord.

The tension in the cord connected to the 7.1 kg block can be found using the same approach. By equating the net force on the block to its mass times its acceleration, we can solve for the tension in the cord.